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The SecOps Group Certified Network Security Practitioner Sample Questions (Q21-Q26):
NEW QUESTION # 21
According to the screenshot below, which of the following statements are correct?
- A. The application is running on port 80 and the HTTP protocol.
- B. The credentials have been submitted over the HTTPS protocol.
- C. The credentials have been submitted over the HTTP protocol.
- D. The application is running on port 443 and the HTTPS protocol.
Answer: D
Explanation:
The screenshot is from Wireshark, a network protocol analyzer, displaying captured network traffic. The relevant columns include the source and destination IP addresses, ports, protocol, and additional information about the packets. Let's break down the details:
Destination Port Analysis: The screenshot shows multiple packets with a destination port of 443 (e.g., in the "Destination" column, entries like "172.72.61.9:443"). Port 443 is the default port for HTTPS (HTTP Secure), which is HTTP traffic encrypted using SSL/TLS. This indicates that the application is communicating over HTTPS.
Protocol Analysis: The "Protocol" column lists "TLSv1.2" for most packets (e.g., frame numbers 2000084, 2000086). TLS (Transport Layer Security) is the cryptographic protocol used by HTTPS to secure HTTP communications. This confirms that the traffic is HTTPS, not plain HTTP.
Packet Details: The "Info" column provides additional context, such as "Application Data" for TLS packets, indicating encrypted application-layer data (typical of HTTPS). There are also HTTP packets (e.g., frame 2000088), but these are likely part of the HTTPS session (e.g., HTTP/2 over TLS, as noted by "HTTP2").
Now, let's evaluate the options:
Option A: "The application is running on port 443 and the HTTPS protocol." This is correct. The destination port 443 and the use of TLSv1.2 confirm that the application is using HTTPS. HTTPS is the standard protocol for secure web communication, and port 443 is its designated port. CNSP documentation emphasizes that HTTPS traffic on port 443 indicates a secure application-layer protocol, often used for web applications handling sensitive data.
Option B: "The credentials have been submitted over the HTTP protocol." This is incorrect. HTTP typically uses port 80, but the screenshot shows traffic on port 443 with TLS, indicating HTTPS. Credentials submitted over this connection would be encrypted via HTTPS, not sent in plaintext over HTTP. CNSP highlights the security risks of HTTP for credential submission due to lack of encryption, which isn't the case here.
Option C: "The credentials have been submitted over the HTTPS protocol." While this statement could be true (since HTTPS is in use, any credentials would likely be submitted securely), the question asks for the "correct" statement based on the screenshot. The screenshot doesn't explicitly show credential submission (e.g., a POST request with form data); it only shows the protocol and port. Option A is more directly supported by the screenshot as it focuses on the application's protocol and port, not the specific action of credential submission. CNSP notes that HTTPS ensures confidentiality, but this option requires more specific evidence of credentials.
Option D: "The application is running on port 80 and the HTTP protocol." This is incorrect. Port 80 is the default for HTTP, but the screenshot clearly shows port 443 and TLS, indicating HTTPS. CNSP documentation contrasts HTTP (port 80, unencrypted) with HTTPS (port 443, encrypted), making this option invalid.
Conclusion: Option A is the most accurate and comprehensive statement directly supported by the screenshot, confirming the application's use of port 443 and HTTPS. While Option C might be true in a broader context, it's less definitive without explicit evidence of credential submission in the captured packets.
NEW QUESTION # 22
WannaCry, an attack, spread throughout the world in May 2017 using machines running on outdated Microsoft operating systems. What is WannaCry?
- A. Malware
- B. Ransomware
Answer: B
Explanation:
WannaCry is a ransomware attack that erupted in May 2017, infecting over 200,000 systems across 150 countries. It exploited the EternalBlue vulnerability (MS17-010) in Microsoft Windows SMBv1, targeting unpatched systems (e.g., Windows XP, Server 2003). Developed by the NSA and leaked by the Shadow Brokers, EternalBlue allowed remote code execution.
Ransomware Mechanics:
Encryption: WannaCry used RSA-2048 and AES-128 to encrypt files, appending extensions like .wcry.
Ransom Demand: Displayed a message demanding $300-$600 in Bitcoin, leveraging a hardcoded wallet.
Worm Propagation: Self-replicated via SMB, scanning internal and external networks, unlike typical ransomware requiring user interaction (e.g., phishing).
Malware Context: While WannaCry is malware (malicious software), "ransomware" is the precise subcategory, distinguishing it from viruses, trojans, or spyware. Malware is a broad term encompassing any harmful code; ransomware specifically encrypts data for extortion. CNSP likely classifies WannaCry as ransomware to focus on its payload and mitigation (e.g., patching, backups).
Why other options are incorrect:
B . Malware: Correct but overly generic. WannaCry's defining trait is ransomware behavior, not just maliciousness. Specificity matters in security taxonomy for threat response (e.g., NIST IR 8019).
Real-World Context: WannaCry crippled NHS hospitals, highlighting patch management's criticality. A kill switch (a domain sinkhole) halted it, but variants persist.
NEW QUESTION # 23
Which of the following protocols is not vulnerable to address spoofing attacks if implemented correctly?
- A. ARP
- B. TCP
- C. IP
- D. UDP
Answer: B
Explanation:
Address spoofing fakes a source address (e.g., IP, MAC) to impersonate or amplify attacks. Analyzing protocol resilience:
C . TCP (Transmission Control Protocol):
Mechanism: Three-way handshake (SYN, SYN-ACK, ACK) verifies both endpoints.
Client SYN (Seq=X), Server SYN-ACK (Seq=Y, Ack=X+1), Client ACK (Ack=Y+1).
Spoofing Resistance: Spoofer must predict the server's sequence number (randomized in modern stacks) and receive SYN-ACK, impractical without session hijacking or MITM.
Correct Implementation: RFC 793-compliant, with anti-spoofing (e.g., Linux tcp_syncookies).
A . UDP:
Connectionless (RFC 768), no handshake. Spoofed packets (e.g., source IP 1.2.3.4) are accepted if port is open, enabling reflection attacks (e.g., DNS amplification).
B . ARP (Address Resolution Protocol):
No authentication (RFC 826). Spoofed ARP replies (e.g., fake MAC for gateway IP) poison caches, enabling MITM (e.g., arpspoof).
D . IP:
No inherent validation at Layer 3 (RFC 791). Spoofed source IPs pass unless filtered (e.g., ingress filtering, RFC 2827).
Security Implications: TCP's handshake makes spoofing harder, though not impossible (e.g., blind spoofing with sequence prediction, mitigated since BSD 4.4). CNSP likely contrasts this with UDP/IP's vulnerabilities in DDoS contexts.
Why other options are incorrect:
A, B, D: Lack handshake or authentication, inherently spoofable.
Real-World Context: TCP spoofing was viable pre-1990s (e.g., Mitnick attack); modern randomization thwarts it.
NEW QUESTION # 24
How would you establish a null session to a Windows host from a Windows command prompt?
- A. net use hostnameipc$ "" /u:NULL
- B. net use hostnamec$ "" /u:NULL
- C. net use hostnameipc$ "" /u:""
- D. net use hostnamec$ "" /u:""
Answer: C
Explanation:
A null session in Windows is an unauthenticated connection to certain administrative shares, historically used for system enumeration. The net use command connects to a share, and the IPC$ (Inter-Process Communication) share is the standard target for null sessions, allowing access without credentials when configured to permit it.
Why C is correct: The command net use hostnameipc$ "" /u:"" specifies the IPC$ share and uses empty strings for the password (first "") and username (/u:""), establishing a null session. This syntax is correct for older Windows systems (e.g., XP or 2003) where null sessions were more permissive, a topic covered in CNSP for legacy system vulnerabilities.
Why other options are incorrect:
A: Targets the c$ share (not typically used for null sessions) and uses /u:NULL, which is invalid syntax; the username must be an empty string ("").
B: Targets c$ instead of ipc$, making it incorrect for null session establishment.
D: Uses ipc$ correctly but specifies /u:NULL, which is not the proper way to denote an empty username.
NEW QUESTION # 25
Which Kerberos ticket is required to generate a Silver Ticket?
- A. Service Account Ticket
- B. Session Ticket
- C. There is no specific ticket required for generating a Silver Ticket
- D. Ticket-Granting Ticket
Answer: A
Explanation:
A Silver Ticket is a forged Kerberos Service Ticket (TGS - Ticket Granting Service) in Active Directory, granting access to a specific service (e.g., MSSQL, CIFS) without KDC interaction. Unlike a Golden Ticket (TGT forgery), it requires:
Service Account's NTLM Hash: The target service's account (e.g., MSSQLSvc) hash, not a ticket.
Forgery: Tools like Mimikatz craft the TGS (e.g., kerberos::golden /service:<spn> /user:<user> /ntlm:<hash>).
Kerberos Flow (RFC 4120):
TGT (Ticket-Granting Ticket): Obtained via AS (Authentication Service) with user creds.
TGS: Requested from TGS (Ticket Granting Service) using TGT for service access.
Silver Ticket Process:
No TGT needed; the attacker mimics the TGS step using the service account's stolen hash (e.g., from a compromised host).
C . Service Account Ticket: Misnomer-it's the hash of the service account (e.g., MSSQLSvc) that enables forgery, not a pre-existing ticket. CNSP's phrasing likely tests this nuance.
Security Implications: Silver Tickets are stealthier than Golden Tickets (service-specific, shorter-lived). CNSP likely stresses hash protection (e.g., LAPS) and Kerberos monitoring.
Why other options are incorrect:
A . Session Ticket: Not a Kerberos term; confuses session keys.
B . TGT: Used for Golden Tickets, not Silver.
D: Incorrect; the service account's hash (implied by "ticket") is essential.
Real-World Context: Silver Tickets exploited in APT29 attacks (2020 SolarWinds) for lateral movement.
NEW QUESTION # 26
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